We can answer this question by looking at the acceleration in the y direction. After the ball leaves Nolan Ryan's hand, the only force acting on it is gravity, in the -y direction.
The equation for distance is d = vt + (1/2)gt^2, where v is the initial velocity of the ball. Since the ball was thrown horizontally, there is no initial downward velocity component to the ball; v = 0.
We know the ball fell .809 m in the time t the ball took to arive at home plate.
.809 = (1/2)(9.81)t^2 --> .165 = t^2
t = 0.41 s
So the ball travelled 18.3 m horizontally in 0.41 s. v = 18.3/0.41 = 44.63 m/s or, 99.83 mph
Note that the official speed for Ryan's pitch is 100.1 mph, thrown in August 1974 at Anaheim Stadium.
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