1 L of water at 20degrees Celsius will occupy what volume at 80 degrees Celsius? Water has a volume expansion coefficient of 210x10^-6/degree...

Given:

Initial volume of water = v = 1 L

Initial temperature = t = 20 degree C

Final temperature = t' = 80 degree C

Volume expansion coefficient = E = 210*10^-6

Let v' be the temperature at final temperature t'

Then v' is given by the formula:

v' = v[(1 + (t' - t)*E] = 1 + (80 - 20)*(210*10^-6)

= 1 + 126*10^-4 = 1 + 0.0126 = 1.0126 L

= 1.013 L (Rounding off to the third decimal place)

Answer:

The water will occupy 1.013 L at 80 degree C. Therefore option B) in the given choices is correct.