Find the average force exerted by the bat on the ball if the two are in contact for 0.0028 s. Answer in units of N.A pitcher throws a 0.15kg...

Given:

Initial velocity = u = 14 m/s

Final velocity = v = -32 m/s

Time taken for change in velocity = t = 0.0028 s

Mass of ball = m = 0.15 kg

We know:

Force exerted = acceleration*mass = a*m, and

Acceleration = a = (v - u)/t

Substituting given value of u,v and t we get

a = (-32 - 14)*0.0028 = -46*0.0028 = 0.1288 m/s^2

Substituting this value of acceleration in equation for force

Force exerted = 0.1288*0.15 = 0.01932 N

Answer: Average force exerted by the bat on ball is 0.01932 N