Monday, June 27, 2011

Sum of interior angle of a hexagon. (6-side polygon) thx

The sum of the interior angles of a hexagon is 720 dgrees.


You can have 6 triangles in a hexagon if you join vertices to the centre. So on account six triangles 6*180 degrees minus the angle at the centre which is 360. or 180*6-360 = 720 degrees is the sum of the interor angles of a six sided  polygon  or hexagon.


In a hexagon,ABCDEFA, join AD, now the sum of interior angles of ABCDEFA is equal to the sum of the interior angles of 2 quadrolaterals,ABCD and ADEF or 360+360 =720 degrees.


You can also think, if ABCDEFA is a hexagon, then the hexagon contains triangle ABC+triangleDEF +a qdrilateral ACDF whose  sum of interior angles is equal to the interior angles of the hexagon.But the sum of the angles of two triangles and a quadrilateral is 2*180+360 dgrees = 720 degrees.Therefore, the sum of the interir angles of a hexagon is 720 degrees.

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