Please not that the kinetic energy information provided in the question is not essential for answering either part a) or part b) of the question. Kinetic energy of first bullet can also be calculated the same way as that that of second bullet.
Given:
Mass of the bullets = m 3.4 g = 3.4/1000 kg = 0.0034 kg
Speed of first bullet = v1 = 42.9 m/s
Speed of second bullet = v2 = 77.4 m/s
Kinetic energy of first bullet = K1 = 3.12869 J
b) Kinetic energy of second Bullet
Kinetic energy (K) of a moving object is given by the formula:
K = (m*v^2)/2
Therefore kinetic energy of the second bullet (K2) is given by:
K2 = (m*v^2)/2 = (0.0034*77.4^2)/2 = 10.184292 J
c) Ratio of kinetic energies
Ratio of kinetic Energies = K2/K1 = 3.12869/10.184292 = 3.255122
Please note that it is not necessary to calculate calculate or know the kinetic energies to calculate the ratio of kinetic energies. It can also be worked out as:
K2/K1 = (v2^2)/(v1^2) = (77.4^2)/(42.9^2) = 3.255122
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