How long does it take to reach its highest point? Answer in units of s. What is velocity when it returns to the level from which it started? ans....

The equation for the velocity for the ball thrown vertically :

v= u+at, where u is the initial velocity a is the retardartion due gravitional acceleration, and t is the time of the motion.

At the highest point the velocity v of the ball is zero.

Therefore, 0=26.3-9.8t or 9.8t=26.3. Therefore, t= 26.3/9.8=2.6837 is the time to reach the heighest point.

The height reached s= ut-(1/2)gt^2 = 26.3(26837)-(1/2)(9.8)(2.6837^2)=35.2903m

Returning tothe ground:

Initial velocity u= 0, final velocity v to be found and acceleraion is the acceleration due to gravitation.The height s=35.2903m

We know that v^2-u^2= 2as

v= sqrt(2as)= sqrt(2*9.8*35.2903)=26.3 m/s towards the earth. It is equival in magnitude to the starting velocity but opposite in direction.