Friday, September 14, 2012

How long after being released does the stone strike the beach below the cliff? Answer in units of s. A student stands at the edge of a cliff and...

The horizontal velocity imparted is not affected by gravity or it does not play a role in the time taken for the stone to land . It is only the gravitation that has a role in the time for the stone to reach the ground. The initial vertical velocity of the stone is 0 m/s and its horizontal velocity .


The vertical displacement , s = 24.4m. the depth of the cliff.


The  law of motion of the stone relating to vertical displacement and time is: (1/2) gt^2 = s............(1)


g=9.8m/s^2 and s=24.4. Substituting the values g=9.8m/s^2 and s=24.4  in  eq (1) we get :


(1/2)9.8t^2= 24.4 or


t= sqrt(2*24.4/9.8) =  2.2315 s is the time the stone takes to land.

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