Given pulling force = f1 = 37.9 N
Angle of application of force = A = 55.2 degrees
Distance moved = 324 m
Other data given in the question is not required for finding the answer.
The pulling force is used partially reduce the effect of gravitational by pushing the bag up and there by reduce the friction, and partially to overcome the kinetic friction.
Thus the frictional force used to overcome kinetic friction (f) is equal to the horizontal component of pulling force applied.
The result is that a force f is applied and a displacement of s is obtained.
Therefore:
f = f1*Cos A = 37.9*Cos 55.2 = 37.9*0.5707 = 21.6295 N
work done = f*s = 21.6295*324 = 7007.9677 J
Answer:
Work done by force of friction on flight bag is 7007.9677 J
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