A 0.59 kg football is thrown with a velocity of 15 m/s to the right. A stationary receiver catches the ball and brings it to rest in 0.018 s.What...

Given

The initial velocity of of ball = u = 15 m/s

Final velocity of ball = v = 0

Time taken to stop the ball = t = 0.018 s

Mass of the ball = 0.59 kg

Therefore acceleration = a = (u - v)/t = -15/0.018 m/s^2

and force f = m*a = 0.59 (-15/0.018) = 491.6666 N approximately

Answer: force exerted on the receiver is 491.6666 N.