A 2.5 kg ball strikes a wall with a velocity of 8.2 m/s to the left. The ball bounces off with a velocity of 6.5 m/s to the right.If the ball is in...

The force is defined as the rate of change in momentum of the body.

The momentum of the ball  is the product of its mass and velocity and it is a vector.

So the momentum of the ball at the time it strike the wall = 2.5 kg*8.2m/s = 20.5kg.m/s left.

The monteum of the ball when it is reflected by the wall = 2.5kg*6.5m/s right =16.25 kg.m/s right=-16.25 kg.m/s considering the left direction.

Therefore, the change in momentum =20.5-(-16.25) =36.75 kg*m/s

Threfore the rate of change of momentum ={36.75kg*m/s}/Time of contact={36.75kg*m/s}/0.22s =167.0455 N is the force exerted by the wall.