I'm not sure this is a 'simultaneous equation' but this is how i'd solve it.
'p' is just the unit, not a variable, so ignore 'p' for now.
Beth and Alex have 155 between them.
Beth has 15 more than Alex. Beth's amount is represented by x and Alex's amount is represented by y. Since Beth has 15 more than Alex, instead of using x for Beth, use (y+15). Now, Alex is y and Beth is (y+15).
The first equation would be: x + y = 155.
Substituting (y+15) for Beth's x, the new equation is:
y + (y+15) = 155
Solve for y: 2y + 15 = 155
2y = 140
y = 70
Beth is x, or (y +15), so x = (70+15)
x = 85
Then you can add 'p'. Alex has 70p and Beth has 85p giving 155p in total.
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