Let A ,B C ,D and E be the persons who push the ball north , north east, east, south east and sothern directions. Resolving the force of each in North and eastern directions , we get:
A; 10 cos 0 = 10N towards north and 10 sin0 =0N east
B:10 cos 45=10/sqrt2Nnorth and 10 sin 45 =10/sqrt2N east
C: 10 cos90 =0N north and 10 sin90 = 10N east
D: 10 cos (-135)= -10/sqrt2 N and 10 sin135 = 10/sqrt2
E: 10 cos 180 = -10 N north and 10 sin 180 =0 east
Therefore: thesum of north components=(10+10/srt2+0-10/sqrt2-10)= 0 and the total of east components =2(10/sqrt2)+10 = 10(2/sqrt2 +10=10(sqrt2+1) N = 24.1421N approximately. Therefore the resultant of 0 north and 24.1421 N towards east is 24.1421 N and in eastern direction.
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