solve 2x-7(x-5)=0

To solve 2x-7(x-5)=0

This is an equation in one variable x with degree one(and so it is a linear equation). The principle of solving this type of equation is by collecting all the unknowns or vaiables, or x's here, on the left and all the knowns or the numbers on the right side of the equation, by simle operations. The simple operations are  adding equals, removing equals, multiplying or dividing by equals (but not dividing zero- mind it!) on both sides which does not imbalance the equation.

On the left side there are two terms, 2x, connected by a minus connector to 7(x-5). Since, -7 is distributive over the two terms inside the brackets by multiplication operation, you can write -7(x-5) like -7*x -7*(-5) = -7x+35 and replace the term -7(x-5) in the expression 2x-7(x-5). This enables us to rewrite the left of the equation as below:

2x-7x+35=0.

2x and -7x are like terms and so 2x-7x is -5x.Therefore,

-5x+35=0

Subtract 35 from both sides of the equation.

-5x+35-35=0-35

Simplify.

-5x=-35.

Divide both sides by -5:

-5x/5=-35/(-5) and simplify to get the solution

x=7