Thursday, May 29, 2014

A rain cloud contain 5.37 x 10 to the seventh power kg of water vapor. The acceleration of gravity is 9.81 m/s^2How long would it take for a 1.53kW...

Given:


mass of water = m = 5.37 x 10^7 kg


Displacement of water required = s = 1.54 km = 1540 m


Acceleration of gravity = g = 9.81 m/s^2


Power of pump = 1.53 kW = 1530 W


Total work or energy required to raise the water to required height is given by formula:


Work = m*g*s* = (5.37 x 10^7)*9.81*1540 = 811.26738 x 10^12


Time take to do this work is given by the formula:


Time = Work/(Power of pump) = (811.26738 x 10^12)/1530


= 530.2401176 x 10^9 s


Answer:It will take 530.240 x 10^9 s for the pump.

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