Bird flies w/ speed of 12.2 over water, drops fish. a=gravity at 9.81. The alt. of bird=5.3. Air resistance=none. What is the bird speed at...

I disagree with the above answer. It is correct about the vertical speed of the fish at impact.  But then it goes on to add the effect of the horizontal speed of the bird.  This is not relevant.  I quote from a site on this topic:

This episode looks at the independence of vertical and horizontal motion. It concerns objects accelerating vertically when projected horizontally or vertically. The crucial concept is that vertical acceleration does not affect horizontal velocity. This explains all projectile motion.

So, the speed of the fish when it hits the water is 10.197 m/s^2.  I got this by using two equations.

First, find the time the fish fell using

distance = .5 at2 where a is the acceleration and t is the time.

We know the distance and the acceleration so

5.3 = .5(9.8)t^2

10.6 =9.8t^2

t^2 = 1.0805 and t = 1.0394

So the fish fell for 1.0394 seconds.

Now we must use the formula for velocity:

v = at

We know acceleration (9.81) and we know time (1.0394) so that gives us

v = 10.197 m/s^2.

The above answer is only incorrect because it goes on to add in the effect of the horizontal motion, which it should not do.

BTW, you can put as much info as you want in the second box.  So you could have said "please help with this physics problem" and then put the whole problem in the second box.