Tuesday, December 8, 2015

Find the coefficient of kinetic friction. A dock worker loading crates on a ship finds that a 15kg crate, initially at rest on a horizontal...

Given:


Mass of crate = m = 15 kg


Force required to set the crate in motion = f1 = 64 N


Force required to keep the crate in moving at constant speed = f2 = 57 N


Acceleration of gravity = g = 9.8 m/s^2


We know:


Coefficient of kinetic friction =


(Force required to keep the crate in moving at constant speed)/(Perpendicular force exerted on the crate)


And:


Perpendicular force exerted on the crate = m*g


Substituting given value of m and g we get:


Perpendicular force exerted on the crate =15*9.8 = 147 N


Substituting this value of perpendicular force and Force required to keep the crate in moving at constant speed in equation for coefficient of kinetic friction we get:


Coefficient of kinetic friction = 57/147 = 0.3878

No comments:

Post a Comment