For mercury to expand from 4.0 cm^3 to 4.1 cm^3, what change in temperature is necessary?Mercury has a volume expansion coefficient of 180x10^-6/C...

The extent of expansion in volume due to increase in temperature ids given by the formula:

v2 - v1 = v1*(t2 - t1)*E

Where:

v1 = initial volume = 4 cm^3 (Given)

v2 = Final volume = 4.1 cm^3 (Given)

t1 = Initial temperature

t2 = Final temperature

E = Volume expansion coefficient = 180*10^(-6)/degree C (Given)

Substituting these values in the above equation we get:

4.1 - 4 = 4*(t2 - t1)*[180*10^(-6)

Therefore: 0.1 = (t2 - t1)*[72*10^(-5)]

Therefore: t2 - t1 =  0.1/[72*10^(-5)] =138.88 degrees C

Rounding this off to nearest whole number:

t2 - t1 = 139 degrees C

Therefore change in temperature necessary for expansion is 139 degrees C.

Thus the option B) is correct.